DM topic guide
Probability
Calculate single, combined and conditional outcomes.
Set up a frequency table or probability tree before calculating — never run numbers blind.
The method — step by step
Single event, combined AND/OR, without replacement, conditional (given that), or binomial (exactly k from n)?
Convert percentages to frequencies using 100, 1 000 or 10 000. Whole numbers are far easier to work with.
Tables work for two conditions. Trees work for sequential events where the denominator changes.
With replacement: denominator stays fixed. Without replacement: subtract one after every draw.
'Given that it is defective' means work only within the defective sub-group — not the full sample.
Convert to a frequency table first
| Defective | OK | Total | |
|---|---|---|---|
| Machine A | 120 | 5,880 | 6,000 |
| Machine B | 200 | 3,800 | 4,000 |
| Total | 320 | 9,680 | 10,000 |
P(B | defective) = 200 ÷ 320 = 62.5% — the answer comes straight off the table.
Use 100, 1,000 or 10,000 as your base — whichever turns the percentages into whole numbers with no messy rounding.
Worked example
Given
Question
What is the probability that the defective component was made by Machine B?
Working
Step 1 — turn percentages into real counts (use 10,000 as the base)
| Machine | Parts made | % defective | Defective count |
|---|---|---|---|
| Machine A | 6,000 | 2% | 120 |
| Machine B | 4,000 | 5% | 200 |
| Total | 10,000 | — | 320 |
Step 2 — we already know it's defective, so only look at those 320
Ignore all 9,680 non-defective parts — they're ruled out. Focus only on the 320 defective ones.
Of those 320 defective parts: 120 came from Machine A, 200 came from Machine B.
Chance it came from Machine B → 200 out of 320 defective parts → 200 ÷ 320
Rules to remember
Write out the table or tree with labels before touching any numbers.
Second draw from 12 items has denominator 11, not 12.
'Given that it is defective' means ignore non-defective components entirely.
P(at least one) = 1 − P(none). It is almost always the faster route.
Exactly k successes from n independent trials. C(n,k) counts the arrangements.
We'll take you to the practice setup so you can choose your session and timing.